Three Friends CodeChef Solution - CodingSoln

There are three friends; let's call them A, B, C. They made the following statements:

Problems Code: THREEFR

Contest : PRATICE(SCHOOL)

A: "I have x Rupees more than B."

B: "I have y rupees more than C."

C: "I have z rupees more than A."

You do not know the exact values of x,y,z. Instead, you are given their absolute values, i.e. X=|x|, Y=|y| and Z=|z|. Note that x, y, z may be negative; "having −r rupees more" is the same as "having r rupees less".

Find out if there is some way to assign amounts of money to A, B, C such that all of their statements are true.

Input

The first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows. The first and only line of each test case contains three space-separated integers X, Y and Z.

Output

For each test case, print a single line containing the string "yes" if the presented scenario is possible or "no" otherwise (without quotes).

Constraints

1≤T≤1,000 1≤X,Y,Z≤1,000

Subtasks

Subtask #1 (30 points):

1≤T≤30

1≤X,Y,Z≤3

Subtask #2 (70 points): original constraints

Example Input

2

1 2 1

1 1 1

Example Output

yes

no

Explanation

Example 1: One possible way to satisfy all conditions is: A has 10 rupees, B has 9 rupees and C has 11 rupees. Therefore, we have x=1, y=−2, z=1.

 Example 2: There is no way for all conditions to be satisfied.

C++ Solution:

#include <bits/stdc++.h>
using namespace std;
using ll=long long;
int main(){

    int t;
    cin>>t;
    while(t--) {

        int x,y,z;
        cin>>x>>y>>z;
        if(x+y+z==2*max(x,max(y,z)))
         cout<<"yes"<<endl;
        else
            cout<<"no"<<endl;


    }
    return 0;
}

C Solution

#include <stdio.h>

int main()
{
	int t;
	scanf("%d",&t);
	for(int i=0;i<t;i++)
	{
	    int x,y,z,m,t;
	    scanf("%d %d %d",&x,&y,&z);
	    t=x+y+z;
	    if(x>y)
	        m=x;
	   else
	        m=y;
	   if(z>m)
	        m=z;
	   if(2*m==t)
	    printf("yes\n");
	   else
	    printf("no\n");
	}
	return 0;
}

Python Solution

for i in range(int(input())):
    X,Y,Z = map(int,input().split())
    if X + Y == Z:
        print("yes")
    elif Y + Z == X:
        print("yes")
    elif X + Z == Y:
        print("yes")
    else:
        print("no")

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